In my previous blog, I have shown how I made an OR gate using a power supply of 5V but sometimes it is the case that you have a power supply of 9V which is usually a battery then the circuit is changed a little bit while the remaining remains the same.
This is a Simple circuit thought to mostly students to make them familiar with the electrical circuit specially to make them familiar with PCB board and some basic functions. The use and practical implementation of this is written in other blogs and the link is inserted with the word 'Blog' click on it to see practical implementation.
Procedure and requirement:
It is easy to create an OR gate circuit using a breadboard. The instruments required are:- IC chip 74LS32 has 14 pins. where pin#14 is VCC, which is connected to the +ve terminal and pin#7 is GND, which is connected to the -ve terminal
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- Two switches at least, those switches will serve as an input.
- The power supply of 5V only if a higher supply is provided then the IC chip will be damaged but as we don't have a constant supply of 5V instead we have a power supply of 9V so we will use a Volt regulator of 5V LM7805 to reduce the voltage from 9V to 5V. this will help us to voltage from 9V to 5V.
- Jump wires to connect the components of the circuit.
- LED light to check whether the circuit is operating perfectly or if there is any damaged gate in the circuit.
- A resistor of resistance about 100 - 110 ohms before giving ground the LED light.
If a higher supply is given it will not show any results due to high resistance. If the resistance is low then it might damage the circuit by learning the LED light and IC.
Truth Table and IC's Structure
You can see whether the circuit is correct or not by following the truth table given below
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You can see the Structure of the Gate inside the IC chip. Each IC has 4 Gate inside it..png)
Click on the Simulator button to check the simulation.
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If you have any type of issue or request leave an comment so that we can handle it